Respuesta :

3r+n2−r+5−2n+2=3r+n2+−r+5+−2n+2=3r+n2+−r+5+−2n+2=(n2)+(−2n)+(3r+−r)+(5+2)=n2+−2n+2r+7
=n2−2n+2r+7
3n+n^2-r+5-2n+2
5+2=7
3n+2n=5n
n^2 -r +5n +7
((IDK what order the variables are suppose to go in put i think I got it in the right order.))