Respuesta :

W0lf93
Answer: x = -1

WORKINGS

We are to solve the cube root equation, ∛x – 1 + 2 = 0

Solve like terms; subtract 1 from 2 to get -1 (-1 + 2 = +1)
Therefore, ∛x + 1 = 0

Move +1 to the right side of the equation, since it does not contain the variable to solve for. 

∛x + 1 = 0
Subtract 1 from both sides of the equation
∛x + 1 – 1 = 0 – 1
∛x = -1

Cube both sides of the equation in order to remove the radical on the left side
(∛x)^3 = (-1)^3
x = -1
calculista

we have

[tex] \sqrt[3]{x} -1+2=0 [/tex]

Step 1

Solve like terms

[tex] \sqrt[3]{x}+(-1+2)=0 [/tex]

[tex] \sqrt[3]{x}+(1)=0 [/tex]

Step 2

Subtract 1 from both sides of the equation

[tex] \sqrt[3]{x}+1-1=0-1 [/tex]

[tex] \sqrt[3]{x}=-1 [/tex]

Step 3

Cube both sides of the equation in order to remove the radical on the left side

[tex] (\sqrt[3]{x})^{3}=(-1 )^{3} \\ x=-1 [/tex]

therefore

the answer is

[tex] x=-1 [/tex]