Perrty1 Perrty1
  • 01-05-2020
  • Mathematics
contestada

I need help on this question thank you

I need help on this question thank you class=

Respuesta :

jimrgrant1 jimrgrant1
  • 01-05-2020

Answer:

[tex]\frac{3xy}{2}[/tex]

Step-by-step explanation:

Given

[tex]\frac{5y^2}{3}[/tex] × [tex]\frac{9x}{10y}[/tex]

Cancel 5y² and 10y by 5y and cancel 3 and 9x by 3, leaving

= [tex]\frac{y}{1}[/tex] × [tex]\frac{3x}{2}[/tex]

= [tex]\frac{3xy}{2}[/tex]

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