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01-05-2020
Chemistry

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A stock solution of 1.00 M Fe2(SO4)3 is available. How many milliliters are
needed to make 0.500 L of 0.750 M?

Respuesta :

SvetkaChem SvetkaChem

01-05-2020

Answer:

375 mL

Explanation:

M1*V1 = M2*V2

M1 = 1.00 M

V1 = ?

M2 = 0.750 M

V2 = 0.500 L

1.00 M * V1 = 0.750 M * 0.500 L

V1 = 0.750*0.500/1.00 = 0.375 L = 375 mL

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