Respuesta :

WojtekR

[tex]\dfrac{x+6}{x+2}=\dfrac{x+3}{x-5}\qquad\qquad\text{cross multiply}\\\\(x+6)(x-5)=(x+2)(x+3)\\\\x^2-5x+6x-30=x^2+3x+2x+6\\\\x^2+x-30=x^2+5x+6\\\\x^2+x-x^2-5x=6+30\\\\-4x=36\quad|:(-4)\\\\\boxed{x=-9}[/tex]

Answer C.