corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

Define the 2 concepts fraud and corruption and give examples of each

In which decade was india MOST economically successful?

Besides advertising new products and services, commercial photography also ____________

Which of the following is an In-kind benefit? a)food stamps b)shares of stock c)economic freedom d)none of the above i think it is c. .

Which of these cells are phagocytes? B cells neutrophils T cells natural killer cells dendritic cells

27+9s=-36 solve for s.

Which of th following statements is true of setting realistic goals? A) It cannot reduce the level of stress in your life B) It can help manage stress levels be

describe 58 as a sum of ten and ones

In 2007 Candace made 37 more field goals than she did in 2006, she had a total of 497 field goals for those years. How many field goals did she make in 2006

PLEASE HELP,what's the answer